A) \[-\text{ }900\text{ }J\]
B) \[-900\text{ }kJ\]
C) \[270\text{ }kJ\]
D) \[900\text{ }kJ\]
Correct Answer: A
Solution :
Work done due to change in volume against constant pressure is \[W=-p({{V}_{2}}-{{V}_{1}})\] \[=-1\times {{10}^{5}}N{{m}^{-2}}(1\times {{10}^{-2}}-1\times {{10}^{-3}}){{m}^{3}}\] \[=-900Nm=-900J\] \[(1\text{ }Nm=1J)\]You need to login to perform this action.
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