A) \[\frac{x}{2}+\frac{y}{3}=-1\]and\[\frac{x}{-2}+\frac{y}{1}=-1\]
B) \[\frac{x}{2}-\frac{y}{3}=-1\]and\[\frac{x}{-2}+\frac{y}{1}=-1\]
C) \[\frac{x}{2}+\frac{y}{3}=1\]and\[\frac{x}{-2}+\frac{y}{1}=1\]
D) \[\frac{x}{2}-\frac{y}{3}\,=1\] and \[\frac{x}{-2}\,+\frac{y}{1}\,=1\]
Correct Answer: D
Solution :
If a and b are intercepts on the X-axis and y-axis respectively, then the equation of the line is \[\frac{x}{a}+\frac{y}{b}=1\]. Let a and b be intercepts on the coordinate axesYou need to login to perform this action.
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