A) 10 mL
B) 20 mL
C) 40 mL
D) 60 mL
Correct Answer: C
Solution :
\[{{H}_{3}}P{{O}_{3}}\]is a dibasic acid (containing two ionisable protons attached to O directly). \[{{H}_{3}}P{{O}_{3}}2{{H}^{+}}+HPO_{4}^{2-}\] \[\therefore \] \[0.1M\,{{H}_{3}}P{{O}_{3}}=0.2\,N\,{{H}_{3}}P{{O}_{3}}\] and \[0.1M\,KOH=0.1\,N\,KOH\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[(KOH)=({{H}_{3}}P{{O}_{3}})\] \[0.1{{V}_{1}}=0.2\times 20\] \[{{V}_{1}}=40\,mL\]
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