JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    Distance between two parallel planes \[2x+y+2z=8\]and\[4x+2y+4z+5=0\]is

    A) \[\frac{3}{2}\]   

    B)                        \[\frac{5}{2}\]                                   

    C) \[\frac{7}{2}\]                   

    D)        \[\frac{9}{2}\]

    Correct Answer: C

    Solution :

    Distance between two parallel planes \[ax+by+cz+{{d}_{1}}=0\]and\[ax+by+cz+{{d}_{2}}=0\]is \[\left| \frac{{{d}_{2}}-{{d}_{1}}}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}} \right|\]. The distance between\[4x+2y+4z-16=0\] and\[4x+2y+4z+5=0\]is. \[\left| \frac{5+16}{\sqrt{16+4+16}} \right|\] \[=\left| \frac{21}{\sqrt{36}} \right|=\frac{21}{6}=\frac{7}{2}\]


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