A) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\]
B) \[C{{H}_{3}}-C{{H}_{2}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ {{C}_{2}}{{H}_{5}} \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-\]
D) \[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\]
Correct Answer: C
Solution :
contains asymmetric carbon, thus optically active.You need to login to perform this action.
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