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JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    A wire fixed at the upper end stretches by length 1 by applying a force\[F\]The work done in stretching is

    A) \[\frac{F}{2l}\]  

    B)                        \[Fl\]                    

    C)        \[2Fl\]                  

    D)        \[\frac{Fl}{2}\]

    Correct Answer: D

    Solution :

    The work done in stretching the wire = Potential energy store \[=\frac{1}{2}\times \] Stress \[\times \] Strain \[\times \] Volume  \[=\frac{1}{2}\times \frac{F}{A}\times \frac{l}{L}\times AL=\frac{1}{2}Fl\]


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