JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    The sides of a triangle are\[\sin \alpha ,\text{ }\cos \alpha \]and\[\sqrt{1+\sin \alpha \cos \alpha }\]for some\[0<\alpha <\frac{\pi }{2}\]. Then, the greatest angle of the triangle is

    A) \[60{}^\circ \]  

    B)                                        \[90{}^\circ \]                   

    C)        \[120{}^\circ \]                 

    D)        \[150{}^\circ \]

    Correct Answer: C

    Solution :

    If a, b and c are the sides of a triangle and C is a largest angle, then Letthen \[\Rightarrow \,\cos C=-\frac{\sin \alpha \cos \alpha }{2\sin \alpha \cos \alpha }\]

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