A) 2.0
B) 4.0
C) 1.6
D) 2.5
Correct Answer: A
Solution :
For a body or system to be in equilibrium net force acting on the body or system should be, zero. i.e., sum of component of all the forces acting in a particular direction is zero. Let the mass of block be m. Frictional force in rest position \[F=mg\text{ }\sin \text{ }30{}^\circ \] (this is static frictional force and may be less than the limiting frictional force) At the condition of equilibrium block on incline. \[10=m\times 10\times \frac{1}{2}\] \[\therefore \] \[m=\frac{2\times 10}{10}=2\,kg\]You need to login to perform this action.
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