A) \[{{\sin }^{-1}}(n)\]
B) \[{{\sin }^{-1}}(1/n)\]
C) \[{{\tan }^{-1}}(1/n)\]
D) \[{{\tan }^{-1}}(n)\]
Correct Answer: D
Solution :
The particular angle of incidence for which reflected light is totally polarised for reflection from air to glass, is called the angle of polarisation\[({{i}_{p}})\] According to Brewster's law, \[n=\tan {{i}_{p}}\] \[\Rightarrow \] \[{{i}_{p}}={{\tan }^{-1}}(n)\] where,\[n=\]refractive index of glass.
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