A) \[1.68V\]
B) \[1.40V\]
C) \[0.91\text{ }V\]
D) \[0.63\text{ }V\]
Correct Answer: C
Solution :
\[Sn(s)+2F{{e}^{3+}}(aq)\xrightarrow{{}}2F{{e}^{2+}}(aq)+S{{n}^{2+}}(aq)\] \[E_{cell}^{o}=E_{ox}^{o}+E_{red}^{o}\] \[=E_{sn/s{{n}^{2+}}}^{o}+E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}\] Given, \[E_{S{{n}^{2+}}/Sn}^{o}=-0.14V\] \[\therefore \] \[E_{Sn/S{{n}^{2+}}}^{o}=+\,0.14\,V\] \[E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}=0.77V\] \[\therefore \] \[E_{cell}^{o}=0.14+0.77=0.91V\]You need to login to perform this action.
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