A) infinite
B) five
C) three
D) zero
Correct Answer: B
Solution :
For possible interference maxima on the screen, the condition is \[d\sin \theta =n\lambda \] ...(i) Given, \[d=slit-width=2\lambda \] \[\therefore \] \[2\lambda \sin \theta =n\lambda \] \[\Rightarrow \] \[2\sin \theta =n\] The maximum value of\[sin\theta \]is 1, hence \[n=2\times 1=2\] Thus, Eq. (i) must be satisfied by 5 integer values i.e., -2, -1, 0, 1, 2. Hence, the maximum number of possible interference maxima is 5.
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