A) \[0.2\text{ }m/{{s}^{2}}\]
B) \[98\text{ }m/{{s}^{2}}\text{ }{{L}^{-1}}\]
C) \[5\text{ }m/{{s}^{2}}\]
D) \[4.8\text{ }m/{{s}^{2}}\]
Correct Answer: A
Solution :
On releasing, the motion of the system will be according to figure. \[{{m}_{1}}g-T={{m}_{1}}a\] ...(i) and \[T-{{m}_{2}}g={{m}_{2}}a\] ...(ii) On solving; \[a=\left( \frac{{{m}_{1}}-{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right)g\] ...(iii) Here, \[{{m}_{1}}=5kg,{{m}_{2}}=4.8kg,g=9.8m/{{s}^{2}}\] \[\therefore \] \[a=\left( \frac{5-4.8}{5+4.8} \right)\times 9.8\] \[=\frac{0.2}{9.8}\times 9.8\] \[=0.2\text{ }m/{{s}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec