A) \[5\mu V\]
B) \[50\mu V\]
C) \[5mV\]
D) \[50\,mV\]
Correct Answer: B
Solution :
The emf induced between ends of conductor, \[e=\frac{1}{2}B\omega {{L}^{2}}\] \[=\frac{1}{2}\times 0.2\times {{10}^{-4}}\times 5\times {{(1)}^{2}}\] \[=0.5\times {{10}^{-4}}V\] \[=5\times {{10}^{-5}}V\] \[=50\mu V\]You need to login to perform this action.
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