A) \[\sqrt{MK}L\]
B) \[\frac{k{{L}^{2}}}{2M}\]
C) zero
D) \[\frac{M{{L}^{2}}}{k}\]
Correct Answer: A
Solution :
Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted into KE. According to conservation of energy, ( for spring)You need to login to perform this action.
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