A) \[\cos \theta \]
B) \[\cot \theta \]
C) \[\sin \theta \]
D) \[\tan \theta \]
Correct Answer: D
Solution :
Electric field due to a charged conducting sheet of surface charge density \[\sigma \] is given by \[E=\frac{\sigma }{{{\varepsilon }_{0}}\,{{\varepsilon }_{r}}}\,=\frac{l}{2{{\varepsilon }_{0}}}\] where,permittivity in vacuum andis relative permittivity of medium. Let the charge on the ball B is Q, then electrostatic force on it FBD of B is shown in figure. In equilibrium, ...(i) and ...(ii) Thus, on dividing Eq. (ii) by Eq. (i), we get orYou need to login to perform this action.
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