A) \[-4\text{ }{{\sin }^{2}}\alpha \]
B) \[4\text{ }{{\sin }^{2}}\alpha \]
C) 4
D) \[2\text{ }{{\sin }^{2}}\alpha \]
Correct Answer: B
Solution :
Given that On squaring both sides, we get \[\Rightarrow \,\,4{{x}^{2}}\,-4\,xy\,\cos \alpha \,={{y}^{2}}\,=4{{\sin }^{2}}\,\alpha \]You need to login to perform this action.
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