A) 6mm
B) 9mm
C) 18mm
D) 12mm
Correct Answer: D
Solution :
The intensity is given by \[l'=l\,{{e}^{-\mu \,\,x}}\] where, \[l=\] intensity of radiation \[-\mu \,x\,=\log \,\frac{l'}{l}\] \[-\mu \,(0.36)=\log \,\frac{l}{8\,l}\] ...(i) Now, intensity is \[\frac{l}{2}\] and thickness is x', then \[-\mu \,x'\,=\log \,\frac{l}{2\,l}\] ...(ii) From Eqs. (i) and (ii), we get \[\therefore \]You need to login to perform this action.
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