2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2005

  • question_answer
    If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately     AIEEE  Solved  Paper-2005

    A) 24.0     

    B)                        25.5                       

    C) 20.5                       

    D)        22.0

    Correct Answer: A

    Solution :

           The relation among mean, mode and median of any frequency distribution is Mode = 3 Median - 2 Mean. Given that, mean = 21 and median = 22 \[\because \] \[Mode=3\text{ }Median-2\text{ }Mean\] \[\therefore \] \[Mode=3(22)-2(21)=66-42=24\]


You need to login to perform this action.
You will be redirected in 3 sec spinner