A) \[400\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[300\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[200\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) None of these
Correct Answer: D
Solution :
Formation of\[XY\]is shown as \[{{X}_{2}}+{{Y}_{2}}\xrightarrow{{}}2XY\] \[\Delta H={{(BE)}_{X-X}}+{{(BE)}_{Y-Y}}-2{{(BE)}_{X-Y}}\] If (BE) of\[XY=a\] Then (BE) of\[(XX)=a\] and (BE)of \[(Y-Y)=\frac{a}{2}\] \[\therefore \] \[\Delta {{H}_{f}}(X-Y)\,\,=-200\,kJ\] \[\therefore \]\[-400\](for 2 mol\[XY\])\[=a+\frac{a}{2}-2a\] \[-400=\frac{a}{2}\] \[a=+800kJ\] The bond dissociation energy \[{{X}_{2}}=800\text{ }kJ\,mo{{l}^{-1}}\]You need to login to perform this action.
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