A) \[_{6}^{12}C\]
B) \[_{5}^{10}B\]
C) \[_{5}^{9}B\]
D) \[_{4}^{11}Be\]
Correct Answer: B
Solution :
As \[_{Z}^{A}X+_{0}^{1}n\,\to \,_{3}^{7}Li\,+_{2}^{4}He\] it implies that and Thus, it is boron .You need to login to perform this action.
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