A) \[\frac{1}{2}{{l}_{0}}\]
B) \[\frac{1}{4}{{l}_{0}}\]
C) zero
D) \[{{l}_{0}}\]
Correct Answer: A
Solution :
From Malus law, the intensity \[l={{l}_{0}}{{\cos }^{2}}\theta \] Intensity of polarised light \[=\frac{{{l}_{0}}}{2}\] Intensity of untransmitted light \[={{l}_{0}}-\frac{{{l}_{0}}}{2}\,=\frac{{{l}_{0}}}{2}\]You need to login to perform this action.
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