A particle is projected from a point O with velocity u at an angle of\[60{}^\circ \]with the horizontal. When it is moving in a direction at right angle to its direction at O, then its velocity is given by
AIEEE Solved Paper-2005
A)\[\frac{u}{\sqrt{3}}\]
B) \[\frac{2u}{3}\]
C)\[\frac{u}{2}\]
D) \[\frac{u}{3}\]
Correct Answer:
A
Solution :
Given, is making an anglewith horizontal (upward). Therefore, v should be atwith horizontal (downward) as shown in figure \[{{v}_{x}}={{u}_{x}}\]