question_answer

A particle is projected from a point O with velocity u at an angle of\[60{}^\circ \]with the horizontal. When it is moving in a direction at right angle to its direction at O, then its velocity is given by     AIEEE  Solved  Paper-2005

A) \[\frac{u}{\sqrt{3}}\]                     

B)        \[\frac{2u}{3}\]                

C) \[\frac{u}{2}\]                  

D)        \[\frac{u}{3}\]

Correct Answer: A

Solution :

Given, is making an anglewith horizontal (upward). Therefore, v should be atwith horizontal (downward) as shown in figure                             \[{{v}_{x}}={{u}_{x}}\]