question_answer

The function \[{{\sin }^{2}}\,(\omega t)\] represents     AIEEE  Solved  Paper-2005

A) a periodic, but not simple harmonic motion with a period \[2\pi /\omega \]

B) a periodic, but not simple harmonic motion with a period \[\pi /\omega \]

C) a simple harmonic motion with a period \[2\pi /\omega \]

D) a simple harmonic motion with a period \[\pi /\omega \]

Correct Answer: B

Solution :

Here, For Hence, function is not SHM, but periodic. From the y-t graph, time period is.