Electrolyte | \[KCl\] | \[KN{{O}_{3}}\] | \[HCl\] | \[NAOAc\] | \[NaCl\] |
\[{{\Lambda }^{\infty }}\] \[(S\,c{{m}^{2}}\,mo{{l}^{-1}})\] | 149.9 | 145.0 | 426.2 | 91.0 | 126.5 |
A) 217.5
B) 390.7
C) 552.7
D) 517.2
Correct Answer: B
Solution :
\[\Lambda _{AcOH}^{\infty }=\Lambda _{AcONa}^{\infty }+\Lambda _{HCl}^{\infty }-\Lambda _{NaCl}^{\infty }\] \[=91.0+426.2-126.5\] \[=390.7\]You need to login to perform this action.
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