Two simple harmonic motions are represented by the equations \[{{y}_{1}}=0.1\sin \left( 100\pi t+\frac{\pi }{3} \right)\]and\[{{y}_{2}}=0.1\,\cos \pi t.\] The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
AIEEE Solved Paper-2005
A)\[\frac{-\pi }{6}\]
B) \[\frac{\pi }{3}\]
C) \[\frac{-\pi }{3}\]
D) \[\frac{\pi }{6}\]
Correct Answer:
A
Solution :
Given, or or and \[{{y}_{2}}=0.1\,\cos \,\pi t\] Hence, phase difference