A) \[{{A}^{n}}={{2}^{n-1}}A+(n-1)l\]
B) \[{{A}^{n}}=nA+(n-1)l\]
C) \[{{A}^{n}}={{2}^{n-1}}A+(n-1)l\]
D) \[{{A}^{n}}=nA+(n-1)l\]
Correct Answer: D
Solution :
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