A straight line through the point A (3, 4) is such that its intercept between the axes is bisected at A. Its equation is
AIEEE Solved Paper-2006
A)\[3x-4y+7=0\]
B)\[4x+3y=24\]
C) \[3x+4y=25\]
D) \[x+y=7\]
Correct Answer:
B
Solution :
Since, A is mid-point of line PQ. \[\therefore \]\[3=\frac{a+0}{2}\] \[\Rightarrow \]\[a=6\] and\[4=\frac{0+b}{2}\] \[\Rightarrow \]\[b=8\] Thus, the equation of line is \[\frac{x}{6}+\frac{y}{8}=1\] or \[4x+3y=24\]