JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    Angle between the tangents to the curve\[y={{x}^{2}}-5x+6\]at the points (2, 0) and (3, 0) is     AIEEE  Solved  Paper-2006

    A) \[\pi /2\]             

    B)        \[\pi /6\]             

    C)        \[\pi /4\]                 

    D)        \[\pi /3\]

    Correct Answer: A

    Solution :

    Since,  \[y={{x}^{2}}-5x+6\] \[\therefore \]\[\frac{dy}{dx}=2x-5\] Now, \[{{m}_{1}}={{\left( \frac{dy}{dx} \right)}_{(2,0)}}=4-5=-1\] and \[{{m}_{2}}={{\left( \frac{dy}{dx} \right)}_{(3,0)}}=6-5=1\] Since, \[{{m}_{1}}{{m}_{2}}=-1\times 1=-1\] \[\therefore \]Angle between the tangents is \[\frac{\pi }{2}\]


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