A) 144 J
B) 288 J
C) 192 J
D) 96 J
Correct Answer: B
Solution :
Here, momentum of the system is remaining conserved as external force is acting on the bomb (system). Initial momentum (before explosion) = Final momentum (after explosion) Let velocity of 4 kg mass be v m/s. From momentum conservation, we can say that its direction is opposite to velocity of 12 kg mass. From \[{{\vec{P}}_{i}}={{\vec{P}}_{f}}\] \[\Rightarrow \] \[0=12\times 4-4\times v\] \[\Rightarrow \] \[v=12\,m/s\] KE of 4kg mass \[=\frac{4\times {{(12)}^{2}}}{2}=288\,J\]You need to login to perform this action.
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