A) \[\left( \frac{x}{x+1} \right)P\]
B) \[\left( \frac{2x}{1-x} \right)P\]
C) \[\left( \frac{x}{x-1} \right)P\]
D) \[\left( \frac{x}{1-x} \right)P\]
Correct Answer: A
Solution :
\[\underset{(1-x)}{\mathop{PC{{l}_{5}}(g)}}\,\underset{x}{\mathop{PC{{l}_{3}}(g)}}\,+\underset{x}{\mathop{C{{l}_{2}}(g)}}\,\] Total number of moles at equilibrium \[=(1-x)+x+x=1+x\] \[{{P}_{PC{{l}_{3}}}}=\left[ \frac{x}{1+x} \right]\times P\]You need to login to perform this action.
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