A) \[O_{2}^{2-}\]
B) \[{{B}_{2}}\]
C) \[N_{2}^{+}\]
D) \[{{O}_{2}}\]
Correct Answer: A
Solution :
\[O_{2}^{2-}\] (Total number of electrons =18) \[\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\] \[\pi 2p_{x}^{2}=\pi 2p_{y}^{2}\] \[\overset{*}{\mathop{\pi }}\,2p_{x}^{2}=\overset{*}{\mathop{\pi }}\,2p_{y}^{2}\]
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