A) \[2.5\times {{10}^{-2}}V\]
B) \[40\,V\]
C) \[250\,V\]
D) \[4\times {{10}^{-3}}\,V\]
Correct Answer: C
Solution :
Trigger to the mind that at resonance, the net impedence of the circuit is equal to net resistance of the circuit i.e., the net reactance of the circuit is must be zero. Remembering that Ohm's law is also valid for AC circuit, At resonance, \[\omega L=\frac{1}{\omega C}\] Current flowing through the circuit, \[l=\frac{{{V}_{R}}}{R}=\frac{100}{1000}=0.1\,A\] So, voltage across L is given by \[{{V}_{L}}=l{{X}_{L}}=l\omega L\] but\[\omega L=\frac{1}{\omega C}\] (at resistance,\[{{X}_{L}}={{X}_{C}}\]) \[\therefore \] \[{{V}_{L}}=\frac{l}{\omega C}=\frac{0.1}{200\times 2\times {{10}^{-6}}}=250\,V\]You need to login to perform this action.
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