A) \[\text{ }8.12\]
B) \[+\text{ }8.612\]
C) \[-37.83\]
D) \[-16.13\]
Correct Answer: D
Solution :
\[Agl(s)+{{e}^{-}}AG(s)+l;\] \[{{E}^{o}}=-0.152\] \[\begin{align} & \underline{Ag(s)\xrightarrow{{}}A{{g}^{+}}+{{e}^{-}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{E}^{o}}=-0.8} \\ & Agl(s)\xrightarrow{{}}A{{g}^{+}}+{{l}^{-}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{E}^{o}}=-0.952 \\ \end{align}\] \[E_{cell}^{o}=\frac{0.059}{1}\log {{K}_{sp}}\] \[-0.952=\frac{0.059}{1}\log {{K}_{sp}}\] \[\log {{K}_{sp}}=\frac{-0.952}{0.059}=-16.135\]You need to login to perform this action.
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