A) inclined at an angle of\[\frac{\pi }{6}\]between them b
B) perpendicular
C) parallel
D) inclined at an angle of\[\frac{\pi }{3}\]between them
Correct Answer: C
Solution :
Since, \[(\vec{a}\times \vec{b})\,\times \vec{c}=\vec{a}\times (\vec{b}\times \vec{c})\] \[\Rightarrow \]\[(\vec{a}.\vec{c})\vec{b}-(\vec{b}.\vec{c})\vec{a}=(\vec{a}.\vec{c}).\vec{b}-(\vec{a}.\vec{b})\vec{c}\] \[\Rightarrow \]\[(\vec{b}.\vec{c})\vec{a}=(\vec{a}.\vec{b})\vec{c}\] \[\Rightarrow \]\[\vec{a}\] is parallel to \[\vec{c}\].You need to login to perform this action.
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