A) 0.01s
B) 10s
C) 0.1s
D) 100s
Correct Answer: A
Solution :
The maximum velocity of a particle performing SHM is given by\[v=A\omega ,\]where A is the amplitude and \[\omega \] is the angular frequency of oscillation. \[\therefore \]\[4.4=(7\times {{10}^{-3}})\times 2\pi /T\] \[\Rightarrow \]\[T=\frac{7\times {{10}^{-3}}}{4.4}\times \frac{2\times 22}{7}=0.01s\]You need to login to perform this action.
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