A) \[-\text{ }14.6\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[-\text{ }16.8\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[+\text{ }16.8\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[+\text{ }244.8\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: C
Solution :
\[\frac{1}{2}{{l}_{2}}(s)+\frac{1}{2}C{{l}_{2}}(g)\xrightarrow{{}}lCl(g)\] \[\Delta H=\left[ \frac{1}{2}\Delta {{H}_{s\to g}}+\frac{1}{2}\Delta {{H}_{diss}}.(C{{l}_{2}})+\frac{1}{2}\Delta {{H}_{diss}}({{l}_{2}}) \right]\] \[-\Delta {{H}_{ICl}}\] \[=\left( \frac{1}{2}\times 62.76+\frac{1}{2}\times 242.3+\frac{1}{2}\times 151.0 \right)-211.3\] \[=228.03-211.3\] \[\Delta H=16.73\,KJ\,mo{{l}^{-1}}\]You need to login to perform this action.
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