A) 0.5 s
B) 0.75 s
C) 0.125s
D) 0.25s
Correct Answer: A
Solution :
To determine the position, velocity etc; at first, we write the general representation of wave and then compare the given wave equation with the general wave equation. Given, \[\sqrt{5}\] This gives, \[\frac{1}{2}(\sqrt{5}-1)\] At \[{{\sin }^{-1}}\left( \frac{x}{5} \right)+co{{\sec }^{-1}}\left( \frac{5}{4} \right)=\frac{\pi }{2},\] \[x\] i.e., the object is at positive extreme, so to acquire maximum speed (i.e., to reach mean position) it takes \[{{(a-b)}^{n}},n\ge 5,\]th of time period. \[\therefore \] Required time\[\frac{a}{b}\] Where, \[\frac{5}{n-4}\] \[\frac{6}{n-5}\] \[\frac{n-5}{6}\] So, required time \[\frac{n-4}{5}\]
You need to login to perform this action.
You will be redirected in
3 sec
