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JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    A Carnot engine, having an efficiency of \[\eta =1/10\] as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is       AIEEE  Solved  Paper-2007

    A)  99 J       

    B)         90 J       

    C)         1 J                         

    D)         100 J

    Correct Answer: B

    Solution :

    For Carnot engine using as refrigerator \[{{e}^{-2}}\] It is given,  \[{{e}^{-1}}\] \[{{e}^{-\frac{1}{2}}}\] \[{{e}^{+\frac{1}{2}}}\] So,          \[2u\times 3v\]                 \[{{\tan }^{-1}}\frac{b}{ac}\]


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