2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    A charged particle with charge g enters a region of constant, uniform and mutually orthogonal fields \[\vec{E}\] and \[\vec{B}\] with a velocity v perpendicular to both \[\vec{E}\] and \[\vec{B}\] and comes out without any change in magnitude or direction of v. Then,       AIEEE  Solved  Paper-2007

    A)  \[\vec{v}=\vec{E}\times \vec{B}/{{B}^{2}}\]

    B)  \[\vec{v}=\vec{B}\times \vec{E}/{{B}^{2}}\]

    C)  \[\vec{v}=\vec{E}\times \vec{B}/{{E}^{2}}\]    

    D)         \[\vec{v}=\vec{B}\times \vec{E}/{{E}^{2}}\]

    Correct Answer: A

    Solution :

    As v of charged particle is remaining constant, it means, force acting on charged particle is zero. So, \[{{\tan }^{-1}}\frac{bc}{a(c-a)}\] \[{{\tan }^{-1}}\frac{bc}{a}\]\[{{y}^{2}}=8x\] \[y=x+2\]\[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-6x-12y-2\text{ }z+20=0,\]


You need to login to perform this action.
You will be redirected in 3 sec spinner