A) \[NO\]
B) \[Si,Ge,Sn\]
C) \[Pb\]
D) \[Ge{{X}_{2}}<Si{{X}_{2}}<Sn{{X}_{2}}<Pb{{X}_{2}}\]
Correct Answer: A
Solution :
Slope of QR \[=\frac{3\sqrt{3}-0}{3-0}\] \[=\sqrt{3}=\tan \theta \] Slope of the line QM \[=\tan \frac{2\pi }{3}=-\sqrt{3}\] The angle between PQR is\[\frac{2\pi }{3},\]so line OM makes an angle\[\frac{2\pi }{3}\]from positive direction of X-axis. Hence, equation of line QM is\[y=-\sqrt{3}x\] or\[\sqrt{3}x+y=0\]You need to login to perform this action.
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