A) \[FH...F\]
B) \[OH...O\]
C) \[OH...F\]
D) \[2Al(s)+6HCl(aq)\xrightarrow[{}]{{}}2A{{l}^{3+}}(aq)\]
Correct Answer: A
Solution :
Using mean value theorem, \[\therefore \]\[f'(c)=\frac{f(3)-f(1)}{3-1}\Rightarrow \frac{1}{c}=\frac{\log 3-\log 1}{2}\] \[\Rightarrow \]\[c=\frac{2}{{{\log }_{e}}3}=2{{\log }_{3}}e\]You need to login to perform this action.
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