A) 1.64
B) 1.88
C) 1.22
D) 1.45
Correct Answer: C
Solution :
\[Molarity=\frac{10\times density\times weight\text{ }of\text{ }solute}{molecular\text{ }weight\text{ }of\text{ }the\text{ }solute}\] \[Density=\frac{3.60\times 98}{10\times 29}=1.21\,gm{{L}^{-1}}\] Alternate Solution Let the density of solution be 'd' Molarity of solution given = 3.6 i.e., 1 litre of solution contains 3.6 moles of\[{{H}_{2}}S{{O}_{4}}\]or 1 litre of solution contains\[3.6\times 98\text{ }g\]of\[{{H}_{2}}S{{O}_{4}}\]. Since, the solution is 29% by mass. \[Density=\frac{molecular\text{ }wt\text{ }of\text{ }the\text{ }solute}{10\times weight\text{ }of\text{ }solute}\] \[=\frac{3.6\times 98}{10\times 29}=1.21gm\,{{L}^{-1}}\]
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