JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    The first and second dissociation constants of an acid \[(E_{cell}^{o}=1.10V),\] are\[Z{{n}^{2+}}\]and \[C{{u}^{2+}}\] respectively. The overall dissociation constant of the acid will be       AIEEE  Solved  Paper-2007

    A)  \[\left( \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]} \right)\]        

    B)         \[{{10}^{37.3}}\]             

    C)         \[9.65\times {{10}^{4}}\]    

    D)         \[p{{K}_{a}}\]

    Correct Answer: C

    Solution :

       \[K={{k}_{1}}\times {{k}_{2}}=1.0\times {{10}^{-5}}\times 5.0\times {{10}^{-10}}\] \[=5\times {{10}^{-15}}\]


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