A)
B)
C)
D)
Correct Answer: D
Solution :
For\[2a/\sqrt{3}\]the diode is reverse biased and hence, offer infinite resistance, so circuit would be like as shown in Fig. (2) given below and \[{{V}_{o}}=0\]. For\[a/\sqrt{3}\]the diode is forward biased and circuit would be as shown in Fig. (3) given below and\[a\sqrt{3}\] Hence, the option (d) is correct.You need to login to perform this action.
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