A) \[=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{({{10}^{-3}})}{2}\]
B) \[{{V}_{A}}-{{V}_{B}}=0\]
C) \[=\frac{\frac{1}{2}qV}{qV}=\frac{1}{2}\]
D) \[I={{I}_{0}}(1-{{e}^{-t/\tau }})\]
Correct Answer: D
Solution :
As phase difference\[I\]path difference i.e., \[{{M}_{O}}\] As \[l={{l}_{\max }}\,{{\cos }^{2}}(\phi /2)\] or \[\frac{l}{{{l}_{0}}}\,={{\cos }^{2}}\,(\phi /2)\] or \[\frac{l}{{{l}_{0}}}\,={{\cos }^{2}}\,(\pi /6)\,\] (where,\[{{l}_{\max }}\,={{l}_{0}}\]) \[{{M}_{O}}{{c}^{2}}\]You need to login to perform this action.
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