A) \[{{I}_{AD}}=4{{I}_{EF}}\]and \[{{I}_{AC}}={{I}_{EF}}\]
B) \[{{I}_{AC}}=\sqrt{2}{{I}_{EF}}\]and\[x={{x}_{0}}\cos (\omega t-\pi /4)\]
C) \[a=A\text{ }cos(\omega t+\delta ),\]and \[A={{x}_{0}},\text{ }\delta =-\pi /4\]
D) \[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =\pi /4\]and\[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =-\pi /4\]
Correct Answer: D
Solution :
\[\frac{{{\mu }_{0}}}{2\pi d}(I_{1}^{2}+I_{2}^{2})\] \[C{{H}_{3}}C{{l}_{2}}+KOH\xrightarrow{\,}:CC{{l}_{2}}\,+\underset{[B]}{\mathop{KCl}}\,+{{H}_{2}}O\]You need to login to perform this action.
You will be redirected in
3 sec