A) butanal
B) n-butyl alcohol
C) n-propyl alcohol
D) propanal
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow{P+{{l}_{2}}}\,\underset{'A'}{\mathop{C{{H}_{2}}C{{H}_{2}}}}\,\,-l\,\xrightarrow{Mg,\,\,ether}\] \[\xleftarrow[{}]{{{H}_{2}}O}\underset{'C'}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\overset{\begin{smallmatrix} OMgl \\ | \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,}}\,\xrightarrow{H-\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,-H}\underset{'B'}{\mathop{C{{H}_{3}}C{{H}_{2}}Mgl}}\,\] \[\begin{align} & \underset{'D'}{\mathop{C{{H}_{3}}C{{H}_{2}}}}\,\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,+Mg(OH)l \\ & \,\,\,\,\,\,\,n-propyl\text{ }alcohol \\ \end{align}\]You need to login to perform this action.
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