A) 7.01
B) 9.22
C) 9.58
D) 4.79
Correct Answer: A
Solution :
\[{{B}^{+}}+{{A}^{-}}+{{H}_{2}}OBOH+HA\] \[pH=\frac{1}{2}p{{K}_{w}}\,+\frac{1}{2}\,p{{K}_{a}}\,-\frac{1}{2}\,p{{K}_{b}}\,=\frac{1}{2}\] (14 + 4.80 ? 4.78) = 7.01You need to login to perform this action.
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