A) \[g\left( y \right)=\frac{y+3}{4}\]
B) \[g\left( y \right)=\frac{y-3}{4}\]
C) \[g\left( y \right)=\frac{3y+4}{3}\]
D) \[g\left( y \right)=4+\frac{y+3}{4}\]
Correct Answer: B
Solution :
Clearly \[f\] is bijective function so it is invertible. \[y=4x+3\Rightarrow \frac{y-3}{4}=x\Rightarrow g\left( y \right)=\frac{y-3}{4}\]
You need to login to perform this action.
You will be redirected in
3 sec
